[libvoikko] Using the Hfst analyser outside of AnalyzerFactory

[Francis Tyers]

El dc 25 de 09 de 2013 a les 20:43 +0300, en/na Harri Pitkänen va
escriure:
> On Wednesday 25 September 2013 14:51:03 Francis Tyers wrote:
> > In grammar/GrammarChecker.hpp, I have defined:
> > 
> > 		RuleEngine * ruleEngine;
> > 		GcCache gc_cache;
> > 		morphology::Analyzer * analyser ;
> > 
> > The class grammar/CgGrammarChecker.hpp extends this and loads:
> > 
> >   * An instance of CgRuleEngine into ruleEngine
> > 
> > I would like to load an instance of HfstAnalyzer into analyser, but I
> > don't see how I can create an instance without using the
> > AnalyzerFactory, which only allows creation using a setup::Dictionary
> > object.
> > 
> > Would it be better to edit AnalyzerFactory and add a method to create
> > analysers only from a path, or is there some other way to get around
> > this ?
> 
> I think you can just call
> 
>   new morphology::HfstAnalyzer(path);
> 
> The constructor is missing an implementation right now but the parameter there 
> is supposed to contain the path to the directory. So no need to use 
> AnalyzerFactory at all. In fact AnalyzerFactory is meant to be used only when 
> you don't know (and don't care) about the concrete implementation that will be 
> created. There is no need to use it when you know you want HfstAnalyzer.

If I try:

        analyser = new morphology::HfstAnalyzer(analyser);

I get:

grammar/CgGrammarChecker.cpp: In constructor
'libvoikko::grammar::CgGrammarChecker::CgGrammarChecker(const string&,
const string&)':
grammar/CgGrammarChecker.cpp:50:50: error: no match for 'operator=' in
'analyser = (operator new(8ul), (<statement>,
((libvoikko::morphology::HfstAnalyzer*)<anonymous>)))'

Any idea ? 

Fran